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Listerabot and template examples

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Re: [Wikidata] [Wiki-Medicine]...

Dennis Tobar

16 Apr 2018 16 Apr '18

11:30 a.m.

Hi: I'm working on protected areas in Chile and I want to get the list using Listeriabot but in a "special format" using templates. I tried to find some example without luck. Does anyone know a working example of Listeriabot + template to render the rows?. Kindly, -- Dennis Tobar Calderón Ingeniero en Informática UTEM

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Antonin Delpeuch (lists)

16 Apr 16 Apr

11:40 a.m.

Hi, It is possible to use templates in Listeria table cells, by tweaking your SPARQL query so that it returns the appropriate wikicode: https://www.wikidata.org/wiki/User:Pintoch/orgid If you have templates which depend on multiple variables in your SPARQL query, I suppose you could take advantage of the fact that the pipe characters in wiki tables can also be used to separate template arguments: you could generate parts of the template in various consecutive SPARQL variables and they would all be rendered as one template in a cell (but the headers would go out of sync). But that's a ugly hack - I would be interested in a cleaner way too. Antonin On 16/04/2018 13:30, Dennis Tobar wrote:

Hi: I'm working on protected areas in Chile and I want to get the list using Listeriabot but in a "special format" using templates. I tried to find some example without luck. Does anyone know a working example of Listeriabot + template to render the rows?. Kindly, -- Dennis Tobar Calderón Ingeniero en Informática UTEM _______________________________________________ Wikidata mailing list Wikidata(a)lists.wikimedia.org https://lists.wikimedia.org/mailman/listinfo/wikidata

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Dennis Tobar

12:19 p.m.

Antonin: Thanks for share your query. I want to create a row with name, year of creation, area protected (in hectare), a photo, the Commons category (if exists) and the legal decree that creates the protected area, so I see that seems impossible to do it with a few concats :) I already have the query and the data from Wikidata, so this isn't the key problem. On Mon, Apr 16, 2018 at 8:40 AM, Antonin Delpeuch (lists) < lists(a)antonin.delpeuch.eu> wrote:

Hi, It is possible to use templates in Listeria table cells, by tweaking your SPARQL query so that it returns the appropriate wikicode: https://www.wikidata.org/wiki/User:Pintoch/orgid If you have templates which depend on multiple variables in your SPARQL query, I suppose you could take advantage of the fact that the pipe characters in wiki tables can also be used to separate template arguments: you could generate parts of the template in various consecutive SPARQL variables and they would all be rendered as one template in a cell (but the headers would go out of sync). But that's a ugly hack - I would be interested in a cleaner way too. Antonin On 16/04/2018 13:30, Dennis Tobar wrote:

Hi: I'm working on protected areas in Chile and I want to get the list using Listeriabot but in a "special format" using templates. I tried to find some example without luck. Does anyone know a working example of Listeriabot + template to render the rows?. Kindly, -- Dennis Tobar Calderón Ingeniero en Informática UTEM _______________________________________________ Wikidata mailing list Wikidata(a)lists.wikimedia.org https://lists.wikimedia.org/mailman/listinfo/wikidata

_______________________________________________ Wikidata mailing list Wikidata(a)lists.wikimedia.org https://lists.wikimedia.org/mailman/listinfo/wikidata

-- Dennis Tobar Calderón Ingeniero en Informática UTEM

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Antonin Delpeuch (lists)

12:25 p.m.

I don't see why it would be impossible… Could you share your query and give the wikicode you would like to generate for a sample row? Antonin On 16/04/2018 14:19, Dennis Tobar wrote:

Antonin: Thanks for share your query. I want to create a row with name, year of creation, area protected (in hectare), a photo, the Commons category (if exists) and the legal decree that creates the protected area, so I see that seems impossible to do it with a few concats :) I already have the query and the data from Wikidata, so this isn't the key problem. On Mon, Apr 16, 2018 at 8:40 AM, Antonin Delpeuch (lists) <lists(a)antonin.delpeuch.eu <mailto:lists@antonin.delpeuch.eu>> wrote: Hi, It is possible to use templates in Listeria table cells, by tweaking your SPARQL query so that it returns the appropriate wikicode: https://www.wikidata.org/wiki/User:Pintoch/orgid <https://www.wikidata.org/wiki/User:Pintoch/orgid> If you have templates which depend on multiple variables in your SPARQL query, I suppose you could take advantage of the fact that the pipe characters in wiki tables can also be used to separate template arguments: you could generate parts of the template in various consecutive SPARQL variables and they would all be rendered as one template in a cell (but the headers would go out of sync). But that's a ugly hack - I would be interested in a cleaner way too. Antonin On 16/04/2018 13:30, Dennis Tobar wrote:

Hi: I'm working on protected areas in Chile and I want to get the list

using

Listeriabot but in a "special format" using templates. I tried to find some example without luck. Does anyone know a working example of Listeriabot + template to render the rows?. Kindly, -- Dennis Tobar Calderón Ingeniero en Informática UTEM _______________________________________________ Wikidata mailing list Wikidata(a)lists.wikimedia.org <mailto:Wikidata@lists.wikimedia.org> https://lists.wikimedia.org/mailman/listinfo/wikidata

<https://lists.wikimedia.org/mailman/listinfo/wikidata>

_______________________________________________ Wikidata mailing list Wikidata(a)lists.wikimedia.org <mailto:Wikidata@lists.wikimedia.org> https://lists.wikimedia.org/mailman/listinfo/wikidata <https://lists.wikimedia.org/mailman/listinfo/wikidata> -- Dennis Tobar Calderón Ingeniero en Informática UTEM _______________________________________________ Wikidata mailing list Wikidata(a)lists.wikimedia.org https://lists.wikimedia.org/mailman/listinfo/wikidata

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Dennis Tobar

12:47 p.m.

Antonin: The query is http://tinyurl.com/yanppn5k and the possible result could be this: https://es.wikipedia.org/wiki/Anexo:Reservas_nacionales_de_Chile#Reservas_n… (columns in es.wiki: photo, year of declaration, name, region, province, area) I want include an icon to Commons if the category exists, and a link to "upload photo" to link an UploadWizard in Commons with the &cat=<cat name> if exists in Commons. (somewhat like as WLM listing in some national contests). In wikitext, it maybe: |- | [[FIle:xxx.jpg|80px|link=]] | {{{name}}} {{#if:{{{commons cat|[[:commons:Category:{{{commons cat}}}|Commons]]}} | {{{year}}} | {{{region}}} | {{{province}}} | {{{area protected}}} | [[File:Missing image icon with camera and upload arrow.svg|80px|link= https://commons.wiki....&cat={{{commons cat}}}]] Kindly On Mon, Apr 16, 2018 at 9:25 AM, Antonin Delpeuch (lists) < lists(a)antonin.delpeuch.eu> wrote:

I don't see why it would be impossible… Could you share your query and give the wikicode you would like to generate for a sample row? Antonin On 16/04/2018 14:19, Dennis Tobar wrote:

Antonin: Thanks for share your query. I want to create a row with name, year of creation, area protected (in hectare), a photo, the Commons category (if exists) and the legal decree that creates the protected area, so I see that seems impossible to do it with a few concats :) I already have the query and the data from Wikidata, so this isn't the key problem. On Mon, Apr 16, 2018 at 8:40 AM, Antonin Delpeuch (lists) <lists(a)antonin.delpeuch.eu <mailto:lists@antonin.delpeuch.eu>> wrote: Hi, It is possible to use templates in Listeria table cells, by tweaking your SPARQL query so that it returns the appropriate wikicode: https://www.wikidata.org/wiki/User:Pintoch/orgid <https://www.wikidata.org/wiki/User:Pintoch/orgid> If you have templates which depend on multiple variables in your

SPARQL

query, I suppose you could take advantage of the fact that the pipe characters in wiki tables can also be used to separate template arguments: you could generate parts of the template in various consecutive SPARQL variables and they would all be rendered as one template in a cell (but the headers would go out of sync). But that's a ugly hack - I would be interested in a cleaner way too. Antonin On 16/04/2018 13:30, Dennis Tobar wrote:

Hi: I'm working on protected areas in Chile and I want to get the list

using > Listeriabot but in a "special format" using templates. I tried to

find

> some example without luck. > > Does anyone know a working example of Listeriabot + template to

render

the rows?. Kindly, -- Dennis Tobar Calderón Ingeniero en Informática UTEM _______________________________________________ Wikidata mailing list Wikidata(a)lists.wikimedia.org <mailto:Wikidata@lists.wikimedia.org> https://lists.wikimedia.org/mailman/listinfo/wikidata

<https://lists.wikimedia.org/mailman/listinfo/wikidata>

_______________________________________________ Wikidata mailing list Wikidata(a)lists.wikimedia.org <mailto:Wikidata@lists.wikimedia.org> https://lists.wikimedia.org/mailman/listinfo/wikidata <https://lists.wikimedia.org/mailman/listinfo/wikidata> -- Dennis Tobar Calderón Ingeniero en Informática UTEM _______________________________________________ Wikidata mailing list Wikidata(a)lists.wikimedia.org https://lists.wikimedia.org/mailman/listinfo/wikidata

_______________________________________________ Wikidata mailing list Wikidata(a)lists.wikimedia.org https://lists.wikimedia.org/mailman/listinfo/wikidata

-- Dennis Tobar Calderón Ingeniero en Informática UTEM

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